In mice, the allele for black fur is dominant to the allele for brown fur. If a male heterozygous black mouse is crossed with a female brown mouse, what percentage of the F1 offspring do you predict will be homozygous? (Enter the number only without the percent sign, e.g., enter 100% as 100 and enter 12.5% as 12.5)
Question
In mice, the allele for black fur is dominant to the allele for brown fur. If a male heterozygous black mouse is crossed with a female brown mouse, what percentage of the F1 offspring do you predict will be homozygous? (Enter the number only without the percent sign, e.g., enter 100% as 100 and enter 12.5% as 12.5)
Solution
To answer this question, we first need to understand the genotypes of the parents.
The male mouse is heterozygous black, which means it has one black fur allele (B) and one brown fur allele (b). So its genotype is Bb.
The female mouse is brown. Since brown is recessive, it must have two brown fur alleles to express this trait. So its genotype is bb.
When these two mice mate, each offspring gets one allele from each parent. The possible combinations are Bb and bb.
The Bb genotype is heterozygous (one black allele, one brown allele), and the bb genotype is homozygous (two brown alleles).
So, the percentage of the F1 offspring that will be homozygous is 50.
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