A body is dropped from a tower with zero velocity reaches the ground in 10s. The height of the tower is about :(given : g = 10 m/s2) A 150 m B 200 m C 50 m D 500 m
Question
A body is dropped from a tower with zero velocity reaches the ground in 10s. The height of the tower is about :(given : g = 10 m/s2) A 150 m B 200 m C 50 m D 500 m
Solution
The height of the tower can be calculated using the second equation of motion, which is:
h = ut + 0.5gt^2
where:
- h is the height of the tower,
- u is the initial velocity of the body,
- t is the time it takes for the body to reach the ground, and
- g is the acceleration due to gravity.
Given that the body is dropped from the tower, the initial velocity u is 0. The time t is given as 10 seconds, and the acceleration due to gravity g is given as 10 m/s^2.
Substituting these values into the equation gives:
h = 010 + 0.51010^2 h = 0 + 0.510*100 h = 0 + 500 h = 500 m
So, the height of the tower is 500 m. The correct answer is D.
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