Sure, here is a Python solution for the problem:

```python
def digital_root_steps(n):
steps = 0
while n 9:
n = sum(int(digit) for digit in str(n))
steps += 1
return n, steps

n = int(input())
root, steps = digital_root_steps(n)

print("Digital Root: ", root)
print("Number of Steps: ", steps)
```

This program works by defining a function `digital_root_steps` that takes an integer `n` as input. It initializes a counter `steps` at 0, then enters a loop that continues as long as `n` is greater than 9. Inside the loop, it converts `n` to a string, iterates over each character (digit) in the string, converts each digit back to an integer, and sums them. This sum becomes the new value of `n`. It also increments `steps` by 1 each time through the loop. When `n` is no longer greater than 9, the function returns `n` (the digital root) and `steps`.

The main part of the program reads an integer from input, calls `digital_root_steps` with this integer, and prints the results.

Question

Sure, here is a Python solution for the problem:

```python
def digital_root_steps(n):
    steps = 0
    while n > 9:
        n = sum(int(digit) for digit in str(n))
        steps += 1
    return n, steps

n = int(input())
root, steps = digital_root_steps(n)

print("Digital Root: ", root)
print("Number of Steps: ", steps)
```

This program works by defining a function `digital_root_steps` that takes an integer `n` as input. It initializes a counter `steps` at 0, then enters a loop that continues as long as `n` is greater than 9. Inside the loop, it converts `n` to a string, iterates over each character (digit) in the string, converts each digit back to an integer, and sums them. This sum becomes the new value of `n`. It also increments `steps` by 1 each time through the loop. When `n` is no longer greater than 9, the function returns `n` (the digital root) and `steps`.

The main part of the program reads an integer from input, calls `digital_root_steps` with this integer, and prints the results.

Knowee AI · Accepted Answer

Sure, here is a Python solution for the problem:

```python
def digital_root_steps(n):
    steps = 0
    while n > 9:
        n = sum(int(digit) for digit in str(n))
        steps += 1
    return n, steps

n = int(input())
root, steps = digital_root_steps(n)

print("Digital Root: ", root)
print("Number of Steps: ", steps)
```

This program works by defining a function `digital_root_steps` that takes an integer `n` as input. It initializes a counter `steps` at 0, then enters a loop that continues as long as `n` is greater than 9. Inside the loop, it converts `n` to a string, iterates over each character (digit) in the string, converts each digit back to an integer, and sums them. This sum becomes the new value of `n`. It also increments `steps` by 1 each time through the loop. When `n` is no longer greater than 9, the function returns `n` (the digital root) and `steps`.

The main part of the program reads an integer from input, calls `digital_root_steps` with this integer, and prints the results.

Question

Solution

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