Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Sodium carbonate is dissolved in water Na2CO3(s) → Na (aq) + CO3 (aq
Question
Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Sodium carbonate is dissolved in water Na2CO3(s) → Na (aq) + CO3 (aq
Solution
The balanced chemical equation for the dissolution of sodium carbonate in water is:
Na2CO3(s) → 2Na+(aq) + CO3^2-(aq)
Here's the step-by-step process:
- Write down the unbalanced equation: Na2CO3 → Na + CO3
- Balance the sodium atoms first. There are 2 sodium atoms on the left side and only 1 on the right side. To balance this, put a 2 in front of Na: Na2CO3 → 2Na + CO3
- Now, balance the carbonate ions. There is 1 carbonate ion on both sides of the equation, so it is already balanced.
- Check to make sure the equation is balanced. There are 2 sodium atoms and 1 carbonate ion on both sides of the equation.
- Finally, insert the ionic charges. Sodium ions have a +1 charge and carbonate ions have a -2 charge: Na2CO3(s) → 2Na+(aq) + CO3^2-(aq)
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