Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Potassium iodide is dissolved in water KI(s) → K (aq) + I (aq)
Question
Balance the following equations by adding the stoichiometric ratios and ionic charges (include the + or - charge). Do not leave the boxes blank or it will mark you incorrect. If the stoichiometry is 1 please insert 1 in the box(es) below. You don't have to add a 1 for the charge.Potassium iodide is dissolved in water KI(s) → K (aq) + I (aq)
Solution
The balanced equation for the dissolution of potassium iodide in water is:
KI(s) → K^(+)(aq) + I^(-)(aq)
The stoichiometric ratios are as follows:
- For KI(s), it is 1.
- For K^(+)(aq), it is 1.
- For I^(-)(aq), it is 1.
The ionic charges are as follows:
- For K^(+)(aq), it is +1.
- For I^(-)(aq), it is -1.
So, the balanced equation with stoichiometric ratios and ionic charges is:
1 KI(s) → 1 K^(+1)(aq) + 1 I^(-1)(aq)
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