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The first four terms of an AP, whose first term is –2 and the common difference is –2, are

Question

The first four terms of an AP, whose first term is –2 and the common difference is –2, are

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Solution

Sure, let's solve this step by step.

  1. The first term (a) of the AP is given as –2.
  2. The common difference (d) is given as –2.

The formula for the nth term of an AP is given by: an=a+(n−1)d a_n = a + (n-1)d

Now, let's find the first four terms:

  1. First term (a₁): a1=a=−2 a_1 = a = -2

  2. Second term (a₂): a2=a+d=−2+(−2)=−4 a_2 = a + d = -2 + (-2) = -4

  3. Third term (a₃): a3=a+2d=−2+2(−2)=−2−4=−6 a_3 = a + 2d = -2 + 2(-2) = -2 - 4 = -6

  4. Fourth term (a₄): a4=a+3d=−2+3(−2)=−2−6=−8 a_4 = a + 3d = -2 + 3(-2) = -2 - 6 = -8

So, the first four terms of the AP are: −2,−4,−6,−8 -2, -4, -6, -8

This problem has been solved

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