What pressure does a 60Kg woman exert on the floor when she balances on one of her heels if each of her heels has an average radius of 1.4cm?Question 12Answera.1055414.01Pab.195414.01Pac.955414.01Pad.9855414.01Pa

The answer is a. 1055414.01Pa.

Step 1: First, we need to calculate the area of the heel that is in contact with the floor. The area (A) of a circle is given by the formula A = πr^2, where r is the radius. In this case, r = 1.4 cm = 0.014 m (since 1 cm = 0.01 m). So, A = π*(0.014 m)^2 = 0.000616 m^2.

Step 2: Next, we need to calculate the force (F) that the woman exerts on the floor. This is given by the formula F = mg, where m is the mass and g is the acceleration due to gravity. In this case, m = 60 kg and g = 9.8 m/s^2 (approximate value). So, F = 60 kg * 9.8 m/s^2 = 588 N.

Step 3: Finally, we can calculate the pressure (P) that the woman exerts on the floor. Pressure is defined as the force per unit area, so P = F/A. In this case, P = 588 N / 0.000616 m^2 = 1055414.01 Pa.

Therefore, the pressure that the woman exerts on the floor is approximately 1055414.01 Pa.