The mass of a boy is 40kg and the area of the sole of his foot is 0.02m2 . If g=10m/s2,calculate the pressure exerted on the floor when he is standing on his i) both feet ii) one foot
Question
The mass of a boy is 40kg and the area of the sole of his foot is 0.02m2 . If g=10m/s2,calculate the pressure exerted on the floor when he is standing on his i) both feet ii) one foot
Solution
i) When the boy is standing on both feet:
The total area in contact with the floor is 2 * 0.02 m^2 = 0.04 m^2.
The force exerted on the floor is the weight of the boy, which is mass * gravity = 40 kg * 10 m/s^2 = 400 N.
Pressure is force divided by area. So, the pressure exerted on the floor is 400 N / 0.04 m^2 = 10,000 Pa (Pascal).
ii) When the boy is standing on one foot:
The area in contact with the floor is 0.02 m^2.
The force exerted on the floor is still the weight of the boy, which is 400 N.
So, the pressure exerted on the floor is 400 N / 0.02 m^2 = 20,000 Pa (Pascal).
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