The given quadratic polynomial is (k – 1)x² + kx + 1.

We know that if -3 is a root of the polynomial, then by substituting x = -3 in the polynomial, it should equal to zero.

So, (-3)²(k - 1) + k*(-3) + 1 = 0
= 9(k - 1) - 3k + 1 = 0
= 9k - 9 - 3k + 1 = 0
= 6k - 8 = 0
= 6k = 8
= k = 8/6 = 4/3

So, the value of k is 4/3. Therefore, the correct answer is A) 4/3.

Question

The given quadratic polynomial is (k – 1)x² + kx + 1.

We know that if -3 is a root of the polynomial, then by substituting x = -3 in the polynomial, it should equal to zero.

So, (-3)²(k - 1) + k*(-3) + 1 = 0
=> 9(k - 1) - 3k + 1 = 0
=> 9k - 9 - 3k + 1 = 0
=> 6k - 8 = 0
=> 6k = 8
=> k = 8/6 = 4/3

So, the value of k is 4/3. Therefore, the correct answer is A) 4/3.

Knowee AI · Accepted Answer

The given quadratic polynomial is (k – 1)x² + kx + 1.

We know that if -3 is a root of the polynomial, then by substituting x = -3 in the polynomial, it should equal to zero.

So, (-3)²(k - 1) + k*(-3) + 1 = 0
=> 9(k - 1) - 3k + 1 = 0
=> 9k - 9 - 3k + 1 = 0
=> 6k - 8 = 0
=> 6k = 8
=> k = 8/6 = 4/3

So, the value of k is 4/3. Therefore, the correct answer is A) 4/3.

If one of the zeroes of the quadratic polynomial (k – 1)x2 + kx + 1 is –3, then the value of k isSelect an answerA4/3B– 4/3C2/3D– 2/3