Jasmine has £1 made up of 10p and 5p coins. She has twice as many tens as fives. How many fives must she have?
Question
Jasmine has £1 made up of 10p and 5p coins. She has twice as many tens as fives. How many fives must she have?
Solution
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First, let's understand the problem. Jasmine has £1 in coins, and all her coins are either 10p or 5p. She has twice as many 10p coins as 5p coins.
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We know that £1 is equal to 100p.
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Let's denote the number of 5p coins as x. According to the problem, Jasmine has twice as many 10p coins as 5p coins, so we can denote the number of 10p coins as 2x.
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The total amount of money Jasmine has in 5p coins is 5x (since each coin is worth 5p) and the total amount she has in 10p coins is 10 * 2x = 20x (since each coin is worth 10p).
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The total amount of money Jasmine has is the sum of the money she has in 5p coins and 10p coins, so we can write the equation: 5x + 20x = 100.
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Simplifying the equation gives 25x = 100.
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Solving for x gives x = 100 / 25 = 4.
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So, Jasmine must have 4 5p coins.
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