Let's denote the number of 25-paisa coins as x and the number of 50-paisa coins as y.

From the problem, we have two equations:

1) x + y = 50 (since the total number of coins is 50)

2) 0.25x + 0.50y = 19.50 (since the total amount of money is Rs.19.50)

We can simplify the second equation by multiplying by 100 to get rid of the decimals:

25x + 50y = 1950

Now we have two equations:

1) x + y = 50

2) 25x + 50y = 1950

We can multiply the first equation by 25 to make the coefficients of y the same in both equations:

25x + 25y = 1250

Now we subtract the first equation from the second:

25x + 50y - (25x + 25y) = 1950 - 1250

This simplifies to:

25y = 700

Finally, we divide by 25 to solve for y:

y = 700 / 25 = 28

Substitute y = 28 into the first equation:

x + 28 = 50

Solving for x gives:

x = 50 - 28 = 22

So, the lady has 22 coins of 25-paisa and 28 coins of 50-paisa.

Question

Let's denote the number of 25-paisa coins as x and the number of 50-paisa coins as y.

From the problem, we have two equations:

1) x + y = 50 (since the total number of coins is 50)

2) 0.25x + 0.50y = 19.50 (since the total amount of money is Rs.19.50)

We can simplify the second equation by multiplying by 100 to get rid of the decimals:

25x + 50y = 1950

Now we have two equations:

1) x + y = 50

2) 25x + 50y = 1950

We can multiply the first equation by 25 to make the coefficients of y the same in both equations:

25x + 25y = 1250

Now we subtract the first equation from the second:

25x + 50y - (25x + 25y) = 1950 - 1250

This simplifies to:

25y = 700

Finally, we divide by 25 to solve for y:

y = 700 / 25 = 28

Substitute y = 28 into the first equation:

x + 28 = 50

Solving for x gives:

x = 50 - 28 = 22

So, the lady has 22 coins of 25-paisa and 28 coins of 50-paisa.

Knowee AI · Accepted Answer