A bag contains one rupees, fifty paisa and 25 paisa in the ratio of 8:9:11, if the total amount in the bag is 122, find no. Of coins of each type?

Sure, let's solve this step by step:

Step 1: Understand the problem The problem states that there are three types of coins in a bag: one rupee, fifty paisa, and twenty-five paisa. These coins are in the ratio of 8:9:11 respectively. The total amount in the bag is 122 rupees. We need to find the number of each type of coin.

Step 2: Convert the ratio into monetary value We know that 1 rupee = 100 paisa. So, the monetary value of the coins in the ratio would be:

• One rupee coins: 8 * 100 = 800 paisa
• Fifty paisa coins: 9 * 50 = 450 paisa
• Twenty-five paisa coins: 11 * 25 = 275 paisa

Step 3: Calculate the total monetary value in paisa The total monetary value in paisa would be 800 + 450 + 275 = 1525 paisa

Step 4: Convert the total amount in the bag into paisa The total amount in the bag is 122 rupees, which is equal to 122 * 100 = 12200 paisa

Step 5: Calculate the value of 1 unit in the ratio The value of 1 unit in the ratio would be 12200 / 1525 = 8 paisa

Step 6: Calculate the number of each type of coin

• Number of one rupee coins: 800 / 8 = 100 coins
• Number of fifty paisa coins: 450 / 8 = 56.25 coins, but since we can't have a fraction of a coin, we'll round this down to 56 coins
• Number of twenty-five paisa coins: 275 / 8 = 34.375 coins, rounding this down gives us 34 coins

So, the bag contains 100 one rupee coins, 56 fifty paisa coins, and 34 twenty-five paisa coins.