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A bag contains rupee, 50 paise and 25 paise coins in the ratio 5:6:8.If the total amount is Rs.420.Find the number of coins of each type.1 ruppe coin= Rs.21050 paise coin = Rs.25225 paise coin = Rs.3361 ruppe coin= Rs.21050 paise coin = Rs.12625 paise coin = Rs.841 ruppe coin= Rs.21050 paise coin = Rs.13225 paise coin = Rs.92None of theseClear ResponseSave & Next

Question

A bag contains rupee, 50 paise and 25 paise coins in the ratio 5:6:8.If the total amount is Rs.420.Find the number of coins of each type.1 ruppe coin= Rs.21050 paise coin = Rs.25225 paise coin = Rs.3361 ruppe coin= Rs.21050 paise coin = Rs.12625 paise coin = Rs.841 ruppe coin= Rs.21050 paise coin = Rs.13225 paise coin = Rs.92None of theseClear ResponseSave & Next

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Solution

The question seems to be a bit confusing as it provides multiple values for the same type of coins. However, I'll try to explain the process using the first set of values.

The total amount is Rs. 420 and the ratio of the coins is 5:6:8 for rupee, 50 paise and 25 paise coins respectively.

First, we need to convert the total amount into paise, as we have coins that are less than a rupee. So, Rs. 420 = 42000 paise.

Next, we find the total ratio by adding the individual ratios: 5 + 6 + 8 = 19.

Now, we find the value of each ratio. The value of each ratio is the total amount divided by the total ratio. So, 42000 paise / 19 = 2210.53 paise.

Now, we find the number of each type of coin by multiplying the value of each ratio by the ratio of that coin.

For rupee coins: 5 * 2210.53 = 11052.63 paise. Since 1 rupee = 100 paise, the number of rupee coins = 11052.63 / 100 = 110.53, which is not possible as the number of coins should be an integer.

Similarly, for 50 paise coins: 6 * 2210.53 = 13263.18 paise. The number of 50 paise coins = 13263.18 / 50 = 265.26, which is also not possible.

For 25 paise coins: 8 * 2210.53 = 17684.24 paise. The number of 25 paise coins = 17684.24 / 25 = 707.37, which is also not possible.

So, none of the given options seem to be correct. Please check the question again.

This problem has been solved

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