emf= dtdΦ B = dtd [ 2Bs (2sx+s 2 )]=Bs 2 dtdx =Bs 2 vTag the questionStep-by-stepFinal solutionSubjectPhysicsSub-subject
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emf= dtdΦ B = dtd [ 2Bs (2sx+s 2 )]=Bs 2 dtdx =Bs 2 vTag the questionStep-by-stepFinal solutionSubjectPhysicsSub-subject
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