Twenty-five percent of element X exists as X-210 and 75 percent of it exists as X-214. What is the atomic weight of element X in amu?1 point85211212213214
Question
Twenty-five percent of element X exists as X-210 and 75 percent of it exists as X-214. What is the atomic weight of element X in amu?1 point85211212213214
Solution
The atomic weight of an element is calculated by taking the sum of the products of the natural abundance and the atomic mass of each isotope. In this case, we have two isotopes: X-210 and X-214.
Step 1: Convert the percentages into decimal form. 25% becomes 0.25 and 75% becomes 0.75.
Step 2: Multiply the atomic mass of each isotope by its natural abundance. For X-210: 0.25 * 210 = 52.5 For X-214: 0.75 * 214 = 160.5
Step 3: Add these two values together to find the atomic weight of element X. 52.5 + 160.5 = 213
So, the atomic weight of element X is 213 amu.
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