Tin-129 is radioactive and has a half life of 2.23 minutes. How long would it take a sample to decay from 2.20mg to 1.90mg.Round your answer to 2 significant digits.

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where: N is the final quantity, N0 is the initial quantity, t is the time, and T is the half-life.

We are given: N0 = 2.20 mg, N = 1.90 mg, and T = 2.23 minutes.

We need to solve for t.

First, we can rearrange the formula to solve for t:

t = T * log(N/N0) / log(1/2)

Substituting the given values into the formula:

t = 2.23 minutes * log(1.90 mg / 2.20 mg) / log(1/2)

Calculating the above expression gives:

t ≈ 1.36 minutes

So, it would take approximately 1.36 minutes for the sample to decay from 2.20 mg to 1.90 mg.

To solve this problem, we need to use the formula for radioactive decay, which is:

N = N0 * (1/2)^(t/T)

where: N is the final quantity, N0 is the initial quantity, t is the time, and T is the half-life.

We are given: N0 = 2.20 mg, N = 1.90 mg, and T = 2.23 minutes.

We need to solve for t.

First, we can rearrange the formula to solve for t:

t = T * log(N/N0) / log(1/2)

Substituting the given values into the formula:

t = 2.23 minutes * log(1.90 mg / 2.20 mg) / log(1/2)

Calculating the above expression gives:

t ≈ 0.63 minutes

So, it would take approximately 0.63 minutes for the sample to decay from 2.20 mg to 1.90 mg.