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alculate the range of a projectile launched with an initial velocity of 30 m/s at an angle of 60°.Select one:a.77.9 mb.90.0 mc.45.0 md.135.0 m

Question

alculate the range of a projectile launched with an initial velocity of 30 m/s at an angle of 60°.Select one:a.77.9 mb.90.0 mc.45.0 md.135.0 m

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Solution

The range of a projectile can be calculated using the formula:

Range = (v²/g) * sin(2θ)

where:

  • v is the initial velocity,
  • g is the acceleration due to gravity, and
  • θ is the launch angle.

Given:

  • v = 30 m/s,
  • g = 9.8 m/s² (approx), and
  • θ = 60°.

We can substitute these values into the formula:

Range = (30²/9.8) * sin(2*60) = (900/9.8) * sin(120) = 91.84 * 0.866 = 79.5 m

So, the closest answer is a. 77.9 m.

This problem has been solved

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