The range of a projectile is maximum, when the angle of projection is:a.60ob.45oc.90od.30o
Question
The range of a projectile is maximum, when the angle of projection is:a.60ob.45oc.90od.30o
Solution
The range of a projectile is given by the formula:
R = (v^2 / g) * sin(2θ)
where: R is the range, v is the initial velocity, g is the acceleration due to gravity, θ is the angle of projection.
The range is maximum when sin(2θ) is maximum. The maximum value of sin(2θ) is 1, which occurs when 2θ = 90 degrees.
Therefore, the range is maximum when the angle of projection θ is 90/2 = 45 degrees.
So, the correct answer is b. 45o.
Similar Questions
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is:A 90° B 60° C 45° D 30°
A projectile is thrown from ground such that itattains maximum possible horizontal range equal to200m. Taking the point of projection as the origin,the coordinates of the point where the velocity of theprojectile is minimum are; (Neglect air resistance)(1) (100, 70) m(2) (200, 50) m(3) (100, 50) m(4) (100, 100) m
The horizontal range of an oblique projectile is equal to the distance through which a projectile has to fall freely from rest to acquire a velocity equal to the velocity of projection in magnitude. The angle of projection isA75oB60oC45oD30o
A projectile is aimed at a mark on a horizontal plane through the point of projection and falls 6 m short when its elevation is 30∘ but overshoot the mark by 9 m when its elevation is 45∘. The angle of elevation of projectile to hit the target on the horizontal plane
The body is projected with same initial velocity for two projectile. Horizontal range of projectiles is same when the angle of projection are:
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.