The following code was run and the output below is shown on the console. Explain the output observed. (4 marks)    <script>      let x = 10;      let y = "10";       if (x == y) console.log ("x is equal y")      if (x !== y) console.log ("x is not equal y")      console.log ("x+y " + (x + y));      console.log ("y*x " + (y * x));    </script>OUTPUTx is equal yx is not equal yx+y 1010y*x 100

The output observed is due to JavaScript's type coercion and comparison rules.

1. if (x == y) console.log ("x is equal y"): This line checks if x is equal to y using the == operator. In JavaScript, the == operator performs type coercion if the variables being compared are not of the same type. Here, x is a number and y is a string. So, JavaScript converts y to a number before the comparison. Since 10 is equal to 10, the condition is true and "x is equal y" is logged to the console.

2. if (x !== y) console.log ("x is not equal y"): This line checks if x is not equal to y using the !== operator. The !== operator is a strict inequality operator that does not perform type coercion. It returns true if the operands are not equal or if they are not of the same type. Since x is a number and y is a string, the condition is true and "x is not equal y" is logged to the console.

3. console.log ("x+y " + (x + y)): This line logs the string "x+y " concatenated with the result of x + y. In JavaScript, when you try to add a number and a string, the number is coerced into a string and then concatenated with the other string. So, x + y results in the string "1010", and "x+y 1010" is logged to the console.

4. console.log ("y*x " + (y * x)): This line logs the string "yx " concatenated with the result of y * x. In JavaScript, when you try to multiply a number and a string, the string is coerced into a number and then the multiplication is performed. So, y * x results in the number 100, and "yx 100" is logged to the console.