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What will be the output of the following program?#include<stdio.h> int main() {     int x = 3;     float y = 3.0;     if(x == y)         printf("x and y are equal");     else         printf("x and y are not equal");     return 0; }Select one:x and y are equalx and y are not equalErrorRandom output

Question

What will be the output of the following program?#include<stdio.h> int main() {     int x = 3;     float y = 3.0;     if(x == y)         printf("x and y are equal");     else         printf("x and y are not equal");     return 0; }Select one:x and y are equalx and y are not equalErrorRandom output

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Solution

The output of the program will be "x and y are equal".

Here's the step by step explanation:

  1. The program starts with the inclusion of the stdio.h header file which is used for input/output operations in C.

  2. The main function is declared which is the entry point of any C program.

  3. Inside the main function, an integer variable 'x' is declared and initialized with the value 3.

  4. A float variable 'y' is also declared and initialized with the value 3.0.

  5. Then there is an if-else statement which checks whether 'x' and 'y' are equal or not.

  6. In C, when comparing an integer and a float, the integer is automatically promoted to a float, and then the comparison is done. So, here 3 is promoted to 3.0 and then compared with 3.0. Since both are equal, the condition in the if statement is true.

  7. Therefore, "x and y are equal" is printed to the console.

  8. The program then returns 0 and ends.

This problem has been solved

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