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The functionย ๐‘˜ย is given byย ๐‘˜๐œƒ=2sin๐œƒ. What are all values ofย ๐œƒ, forย 0โ‰ค๐œƒ<2๐œ‹, whereย ๐‘˜๐œƒ=-1ย ?

Question

The functionย ๐‘˜ย is given byย ๐‘˜๐œƒ=2sin๐œƒ. What are all values ofย ๐œƒ, forย 0โ‰ค๐œƒ<2๐œ‹, whereย ๐‘˜๐œƒ=-1ย ?

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Solution

To find the values of ๐œƒ where ๐‘˜๐œƒ = -1, we first set the function ๐‘˜๐œƒ equal to -1 and solve for ๐œƒ.

2sin๐œƒ = -1

We divide both sides by 2 to isolate sin๐œƒ:

sin๐œƒ = -1/2

Now we need to find the values of ๐œƒ in the interval 0โ‰ค๐œƒ<2๐œ‹ where the sine function equals -1/2.

The sine function equals -1/2 at ๐œƒ = 7๐œ‹/6 and ๐œƒ = 11๐œ‹/6 in the interval 0โ‰ค๐œƒ<2๐œ‹.

So, the values of ๐œƒ where ๐‘˜๐œƒ = -1 are ๐œƒ = 7๐œ‹/6 and ๐œƒ = 11๐œ‹/6.

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