If the cost of parking a car in a parking lot at the railway station is 5 for the first hour or any part thereof, plus 2 for each additional hour or part there of. Which of the relations best represents the cost C as a function of time (t) in hours? [x] is the least integer greater than or equal to x and [x] is the greatest integer less than or equal to x.

Sadie is deciding between two parking garages. Garage A charges an initial fee of $7 to park plus $4 per hour. Garage B charges an initial fee of $3 to park plus $5 per hour. Let AA represent the amount Garage A would charge if Sadie parks for tt hours, and let BB represent the amount Garage B would charge if Sadie parks for tt hours. Write an equation for each situation, in terms of t, commat, and determine which garage would be cheaper if Sadie needs to park for 7 hours.AnswerAttempt 1 out of 2A, equalsA= B, equalsB= is $ cheaper than when parking for 7 hours.

Problem StatementJohn, a software developer in a new city, is seeking your assistance to create a call-by-value function that calculates parking charges for his car trips. The program takes user inputs for the parking spot type ('c' for compact, 'b' for basic, 't' for premium) and total parking time in hours. It then calculates and displays the total parking charge based on predefined rates for each spot type (2 times for compact, 3 times for basic, and 4 times for premium).Function Specifications: float parkingCharge(char s, float parkingtime)Input format :The first line of input consists of a character, representing the type of parking spot ('c' for compact, 'b' for basic, and 't' for premium).The second line consists of a floating-point value, representing the total parking time in hours.Output format :The output displays a floating-point value, representing the total parking charge, rounded off to two decimal places.Refer to the sample output for formatting specifications.Code constraints :In this scenario, the test cases fall under the following constraints:Parking spot - 'c' for compact, 'b' for basic, and 't' for premium1.00 ≤ parking time ≤ 500.00Sample test cases :Input 1 :c1.75Output 1 :3.50Input 2 :b10.25Output 2 :30.75Input 3 :t475.50Output 3 :1902.00

If a train runs at 40 km/h, it reaches its destination late by 11 min, but if it runs at 50 km/h, it is late by 5 min only. The correct time for the train to complete its journey isA12 minB16 minC19 minD25 minSolutionThe correct option is C 19 minLet the correct time to complete the journey be x minutes.Distance covered in (x+11) min at 40 km/h.= Distance covered in (x+5) min at 50 km/h∴(x+11)60×40=(x+5)60×50⇒x=19minSuggest Corrections68SIMILAR QUESTIONSQ. Q40. If a train runs at 40 km/h, it reaches its destination late by 11 min, but if it runs at 50 km/h, it is late by 5 min only. The correct time for the train to complete its journey isQ. If a train runs at 40 km/hr, it reaches its destination late by 11 minutes, but if it runs at 50 km/hr, it is late by 5 minutes only. The correct time for the train to complete the journey isQ. If a train runs at 40 kmph it reaches its destination late by 11 minutes. But if it runs at 50 kmph it is late by 5 minutes only. Find the distance covered by the train.Q. Choose the correct answer from the alternatives given.If a train runs at 70 km/hr, it reaches its destination late by 12 minutes. But if it runs at 80 km/hr. it is late by 3 minutes. The correct lime to cover the journey isQ. If a train runs at 40 kmph, it reaches the destination 15 minutes late. But if the train runs at 50 kmph, it is late by 5 minutes. Find the distance covered by the train.View MoreRELATED VIDEOSSpeed-Distance-TimeQUANTITATIVE APTITUDEWatch in AppEXPLORE MOREMeeting PointOther Quantitative Aptitude

The cost, in dollars, of a one-day car rental is given by C(x) = 31 + 0.18x, where x is the number of miles driven. In this function,

The cost of renting a kayak is $12 for the first hour plus another $5 for each additional hour. Which of the following represents this situation, where C is the total cost of renting a kayak for h hours?A.C = 5h + 12B.C = 17hC.C = 5(h - 1) + 12D.C = 12h + 5SUBMITarrow_backPREVIOUS