The speed of the particle can be calculated using the Pythagorean theorem, as the motion in the x and y directions are independent of each other.

Step 1: Calculate the velocity in the y-direction after 2 seconds.
The velocity in the y-direction can be calculated using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.
Here, u = 0 (as the particle initially moves only along the x-axis), a = 1.5 m/s² (the acceleration), and t = 2 s.
So, v = 0 + 1.5*2 = 3 m/s.

Step 2: Calculate the resultant velocity.
The particle is moving along the x-axis with a velocity of 4 m/s and along the y-axis with a velocity of 3 m/s. These two velocities are perpendicular to each other, so the resultant velocity (or speed) can be calculated using the Pythagorean theorem:
v = sqrt((4 m/s)² + (3 m/s)²) = sqrt(16 + 9) = sqrt(25) = 5 m/s.

So, the speed of the particle after 2 seconds is 5 m/s.

Question

The speed of the particle can be calculated using the Pythagorean theorem, as the motion in the x and y directions are independent of each other.

Step 1: Calculate the velocity in the y-direction after 2 seconds.
The velocity in the y-direction can be calculated using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.
Here, u = 0 (as the particle initially moves only along the x-axis), a = 1.5 m/s² (the acceleration), and t = 2 s.
So, v = 0 + 1.5*2 = 3 m/s.

Step 2: Calculate the resultant velocity.
The particle is moving along the x-axis with a velocity of 4 m/s and along the y-axis with a velocity of 3 m/s. These two velocities are perpendicular to each other, so the resultant velocity (or speed) can be calculated using the Pythagorean theorem: 
v = sqrt((4 m/s)² + (3 m/s)²) = sqrt(16 + 9) = sqrt(25) = 5 m/s.

So, the speed of the particle after 2 seconds is 5 m/s.

Knowee AI · Accepted Answer

The speed of the particle can be calculated using the Pythagorean theorem, as the motion in the x and y directions are independent of each other.

Step 1: Calculate the velocity in the y-direction after 2 seconds.
The velocity in the y-direction can be calculated using the equation v = u + at, where u is the initial velocity, a is the acceleration, and t is the time.
Here, u = 0 (as the particle initially moves only along the x-axis), a = 1.5 m/s² (the acceleration), and t = 2 s.
So, v = 0 + 1.5*2 = 3 m/s.

Step 2: Calculate the resultant velocity.
The particle is moving along the x-axis with a velocity of 4 m/s and along the y-axis with a velocity of 3 m/s. These two velocities are perpendicular to each other, so the resultant velocity (or speed) can be calculated using the Pythagorean theorem: 
v = sqrt((4 m/s)² + (3 m/s)²) = sqrt(16 + 9) = sqrt(25) = 5 m/s.

So, the speed of the particle after 2 seconds is 5 m/s.

A particle moving with a velocity of 4 m/s along x-axis accelerates at a constant rate of 1.5 m/s2 along y-axis. The speed (in m/s) of the particle after 2 seconds isGroup of answer choices53241.5

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