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1 pointHow does Bubble Sort compare elements in an array? Compares adjacent elements and swaps if they are in the wrong order Compares random elements in the array Compares all elements with the first element Compares elements in reverse order

Question

1 pointHow does Bubble Sort compare elements in an array? Compares adjacent elements and swaps if they are in the wrong order Compares random elements in the array Compares all elements with the first element Compares elements in reverse order

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Solution

Bubble Sort compares adjacent elements in an array and swaps them if they are in the wrong order. Here's a step-by-step explanation:

  1. Start from the first element in the array, compare it with the next element.
  2. If the first element is greater than the next, swap them. If not, move to the next pair of elements.
  3. Continue this process for each pair of adjacent elements in the array.
  4. Repeat the entire process for the array until no more swaps are needed. This means the array is now sorted.

This method of sorting is called Bubble Sort because with each complete pass, the largest element "bubbles" up to its correct position.

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Similar Questions

How does Bubble Sort work?By selecting the smallest element and swapping it to the front.By repeatedly swapping adjacent elements if they are in the wrong order.By dividing the array and merging it back together in sorted order.By finding the median and partitioning the array around it.

Bubble Sort is the simplest sorting algorithm that works by repeatedly swapping the adjacent elements if they are in the wrong order. The problem with bubble sort is its worst case scenario. When the smallest element is in the last position, then it takes more time to sort in ascending order, but takes less time to sort in descending order.An array is called beautiful if all the elements of the array are in either ascending or descending order. Given an array of numbers, find the minimum swap operations required to make the array beautiful.

If the array had been sorted in descending order initially, how many swaps would the Bubble Sort perform?

What is the array after the first pass of the Bubble Sort algorithm?

Sorting ProgramIn answering each questions, consider the program below:#include <iostream>#include <algorithm>using namespace std;// Function to perform Bubble Sort on an arrayvoid bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - 1 - i; j++) { // Swap if the element found is greater than the next element if (arr[j] > arr[j + 1]) { swap(arr[j], arr[j + 1]); } } }}int main() { // Given array of 10 numbers int numbers[] = {4, 2, 7, 1, 9, 5, 8, 3, 10, 6}; int n = sizeof(numbers) / sizeof(numbers[0]); // Call the bubbleSort function to sort the array bubbleSort(numbers, n); // Display the sorted array cout << "Sorted array: "; for (int i = 0; i < n; i++) { cout << numbers[i] << " "; } return 0;}---------------------------------------------------------------------------Definition of Terms in the given questions below:In the context of the Bubble Sort algorithm, a "pass" refers to a complete iteration through the array. During each pass, the algorithm compares adjacent elements and swaps them if they are in the wrong order. After each pass, the largest unsorted element is guaranteed to be in its correct position.The number of passes needed to sort an array of size n is generally n - 1. This is because, after the first pass, the largest element is in its correct place, and after the second pass, the second largest element is in its correct place, and so on. After n - 1 passes, the smallest element is also in its correct place, and the array is fully sorted.For example, if you have an array of 5 elements, you would typically need 4 passes to sort it. Each pass contributes to placing one more element in its correct position within the sorted portion of the array.

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