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Balance the following equations by adding the stoichiometric ratios and inserting their physical state (s, l, g or aq).  Do not leave the boxes blank or it will mark you incorrect.  If the stoichiometry is 1 please insert 1 in the box(es) below.  Iron reacts with oxygen to form iron(III) oxide (rust). Fe( )   +    O2( )   →    Fe2O3( )

Question

Balance the following equations by adding the stoichiometric ratios and inserting their physical state (s, l, g or aq).  Do not leave the boxes blank or it will mark you incorrect.  If the stoichiometry is 1 please insert 1 in the box(es) below.  Iron reacts with oxygen to form iron(III) oxide (rust). Fe( )   +    O2( )   →    Fe2O3( )

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Solution

The balanced chemical equation for the reaction of iron with oxygen to form iron(III) oxide is:

4Fe(s) + 3O2(g) → 2Fe2O3(s)

Here's the step-by-step process:

  1. Write the unbalanced equation: Fe(s) + O2(g) → Fe2O3(s)

  2. Balance the iron atoms first. There are 2 iron atoms in Fe2O3 on the right side of the equation, so we put a coefficient of 2 in front of Fe on the left side: 2Fe(s) + O2(g) → Fe2O3(s)

  3. Now balance the oxygen atoms. There are 3 oxygen atoms in Fe2O3 on the right side, and 2 oxygen atoms in O2 on the left side. To balance this, we put a coefficient of 3/2 in front of O2: 2Fe(s) + 3/2O2(g) → Fe2O3(s)

  4. However, we cannot have a fraction as a coefficient in a balanced chemical equation. To get rid of the fraction, we multiply all coefficients by 2: 4Fe(s) + 3O2(g) → 2Fe2O3(s)

So, the stoichiometric ratios are 4:3:2 for Fe, O2, and Fe2O3 respectively.

This problem has been solved

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