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. If ๐‘ฆ = ๐‘ข 2 โˆ’ 2๐‘ข and ๐‘ข = ๐‘ฅ 2 โˆ’ ๐‘ฅ find ๐‘‘๐‘ฆ ๐‘‘๏ฟฝ

Question

. If ๐‘ฆ = ๐‘ข 2 โˆ’ 2๐‘ข and ๐‘ข = ๐‘ฅ 2 โˆ’ ๐‘ฅ find ๐‘‘๐‘ฆ ๐‘‘๏ฟฝ

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Solution

To find dy/dx, we first need to find dy/du and du/dx, then we can use the chain rule.

Given y = u^2 - 2u, we can differentiate y with respect to u to get dy/du.

dy/du = 2u - 2

Next, given u = x^2 - x, we can differentiate u with respect to x to get du/dx.

du/dx = 2x - 1

Now we can use the chain rule, which states that dy/dx = dy/du * du/dx.

So, dy/dx = (2u - 2) * (2x - 1)

But we know that u = x^2 - x, so we can substitute u back into the equation to get dy/dx in terms of x.

dy/dx = (2(x^2 - x) - 2) * (2x - 1)

This is the derivative of y with respect to x.

This problem has been solved

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