The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 4, b = 18, and c = 17.

To solve this equation, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Substituting the values of a, b, and c into the formula, we get:

x = [-18 ± sqrt((18)^2 - 4*4*17)] / (2*4)
x = [-18 ± sqrt(324 - 272)] / 8
x = [-18 ± sqrt(52)] / 8
x = [-18 ± 2sqrt(13)] / 8
x = -9/4 ± sqrt(13)/4

So, the solutions to the equation 4x^2 + 18x + 17 = 0 are x = -9/4 + sqrt(13)/4 and x = -9/4 - sqrt(13)/4.

Question

The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 4, b = 18, and c = 17.

To solve this equation, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Substituting the values of a, b, and c into the formula, we get:

x = [-18 ± sqrt((18)^2 - 4*4*17)] / (2*4)
x = [-18 ± sqrt(324 - 272)] / 8
x = [-18 ± sqrt(52)] / 8
x = [-18 ± 2sqrt(13)] / 8
x = -9/4 ± sqrt(13)/4

So, the solutions to the equation 4x^2 + 18x + 17 = 0 are x = -9/4 + sqrt(13)/4 and x = -9/4 - sqrt(13)/4.

Knowee AI · Accepted Answer

The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 4, b = 18, and c = 17.

To solve this equation, we can use the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).

Substituting the values of a, b, and c into the formula, we get:

x = [-18 ± sqrt((18)^2 - 4*4*17)] / (2*4)
x = [-18 ± sqrt(324 - 272)] / 8
x = [-18 ± sqrt(52)] / 8
x = [-18 ± 2sqrt(13)] / 8
x = -9/4 ± sqrt(13)/4

So, the solutions to the equation 4x^2 + 18x + 17 = 0 are x = -9/4 + sqrt(13)/4 and x = -9/4 - sqrt(13)/4.

Solve the equation 4, x, squared, plus, 18, x, plus, 17, equals, 04x 2 +18x+17=0

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