Sure, here is a Python function that does what you asked for:

```python
def nth_character(a, n):
if n

Question

Sure, here is a Python function that does what you asked for:

```python
def nth_character(a, n):
    if n <= len(a):
        return a[n-1]
    else:
        return "Index out of range"
```

This function takes a string `a` and a number `n` as arguments. It checks if `n` is less than or equal to the length of the string `a`. If it is, it returns the `n`th character of `a` (Python uses 0-based indexing, so we subtract 1 from `n`). If `n` is greater than the length of `a`, it returns a message saying "Index out of range".

Knowee AI · Accepted Answer

Sure, here is a Python function that does what you asked for:

```python
def nth_character(a, n):
    if n <= len(a):
        return a[n-1]
    else:
        return "Index out of range"
```

This function takes a string `a` and a number `n` as arguments. It checks if `n` is less than or equal to the length of the string `a`. If it is, it returns the `n`th character of `a` (Python uses 0-based indexing, so we subtract 1 from `n`). If `n` is greater than the length of `a`, it returns a message saying "Index out of range".

Write a function that takes a string (a) and a number (n) as argument. Return the nth character of 'a'.

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