Fizz Buzz is a classic interview question that apparently many engineering candidates can't solve!We're given a number in the form of an integer n.Write a function that returns the string representation of all numbers from 1 to n based on the following rules:If it's a multiple of 3, represent it as "fizz".If it's a multiple of 5, represent it as "buzz".If it's a multiple of both 3 and 5, represent it as "fizzbuzz".If it's neither, just return the number itself.Input FormatFirst line of input contains T denoting the number of testcases. For each testcase there will be an integer N.Constraints1 < N < 99Output Formatfizz, buzz or fizzbuzz (depending on the integer)Sample Input 013Sample Output 012fizzSample Input 1229Sample Output 11212fizz4buzzfizz78fizz
Question
Fizz Buzz is a classic interview question that apparently many engineering candidates can't solve!We're given a number in the form of an integer n.Write a function that returns the string representation of all numbers from 1 to n based on the following rules:If it's a multiple of 3, represent it as "fizz".If it's a multiple of 5, represent it as "buzz".If it's a multiple of both 3 and 5, represent it as "fizzbuzz".If it's neither, just return the number itself.Input FormatFirst line of input contains T denoting the number of testcases. For each testcase there will be an integer N.Constraints1 < N < 99Output Formatfizz, buzz or fizzbuzz (depending on the integer)Sample Input 013Sample Output 012fizzSample Input 1229Sample Output 11212fizz4buzzfizz78fizz
Solution
To solve the Fizz Buzz problem, we need to write a function that takes an integer n as input and returns the string representation of all numbers from 1 to n based on the given rules.
Here are the steps to solve the problem:
-
Read the number of test cases, T, from the input.
-
For each test case, do the following: a. Read the integer N from the input. b. Initialize an empty string, result. c. Iterate from 1 to N (inclusive) using a loop. d. For each number, check the following conditions:
- If the number is divisible by both 3 and 5, append "fizzbuzz" to the result.
- If the number is divisible by 3, append "fizz" to the result.
- If the number is divisible by 5, append "buzz" to the result.
- If none of the above conditions are met, append the number itself to the result. e. Print the result.
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Repeat step 2 for all test cases.
Here is the code implementation in Python:
# Step 1
T = int(input())
# Step 2
for _ in range(T):
# Step 2a
N = int(input())
result = ""
# Step 2c
for i in range(1, N+1):
# Step 2d
if i % 3 == 0 and i % 5 == 0:
result += "fizzbuzz"
elif i % 3 == 0:
result += "fizz"
elif i % 5 == 0:
result += "buzz"
else:
result += str(i)
# Step 2e
print(result)
This code will take the number of test cases as input, and for each test case, it will take an integer N as input. Then, it will generate the string representation of numbers from 1 to N based on the given rules and print the result.
Similar Questions
Given a number n, for each integer i in the range from 1 to n inclusive, print one value per line as follows: If i is a multiple of both 3 and 5, print FizzBuzz.If i is a multiple of 3 (but not 5), print Fizz.If i is a multiple of 5 (but not 3), print Buzz.If i is not a multiple of 3 or 5, print the value of i.
if given number is a multiple of both 3 and 5 prints "FizzBuzz" instead of numberif given number is a multiple of 3 but not 5 prints "Fizz" instead of numberif given number is a multiple of 5 but not 3 prints "Buzz" instead of numberif given number is not multiple of 3 or 5 prints value as usual.
In a classroom quiz game, students are asked to respond to specific rules related to numbers. Write a Python program, along with an algorithm, that takes a positive integer as input and returns the following based on the following conditions:• "Fizz Buzz" if the number is divisible by both 3 and 5.• "Fizz" if the number is divisible by 3.• "Buzz" if the number is divisible by 5.• The number as a string for all other cases.Input: A positive integer (int).Output: A string (str) representing the response based on the divisibility rules.
class Result { /* * Complete the 'fizzBuzz' function below. * * The function accepts INTEGER n as parameter. */ public static void fizzBuzz(int n) { // Write your code here }}public class Solution {
Looping-3Read an integer natural number N. Print the range of numbers(1 to N) followed by the string 'VIT' if the number is a multiple of 5 else print 'VIT'.Sample Input5Sample OutputVITVITVITVIT5 VIT
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