Looping-3Read an integer natural number N. Print the range of numbers(1 to N) followed by the string 'VIT' if the number is a multiple of 5 else print 'VIT'.Sample Input5Sample OutputVITVITVITVIT5 VIT
Question
Looping-3Read an integer natural number N. Print the range of numbers(1 to N) followed by the string 'VIT' if the number is a multiple of 5 else print 'VIT'.Sample Input5Sample OutputVITVITVITVIT5 VIT
Solution
The problem is asking to print a range of numbers from 1 to N, where N is a natural number input by the user. If the number is a multiple of 5, it should print the number followed by the string 'VIT'. If the number is not a multiple of 5, it should just print 'VIT'.
Here is a step-by-step solution in Python:
- First, we need to read an integer from the user. We can use the
input()function for this, which reads a line of text from the user. Since this function returns a string, we need to convert this string to an integer using theint()function.
N = int(input())
- Next, we need to loop over the range of numbers from 1 to N. In Python, we can use the
range()function to generate this range of numbers. Note that therange()function generates numbers up to, but not including, the end value, so we need to add 1 to N.
for i in range(1, N+1):
- Inside the loop, we need to check if the current number
iis a multiple of 5. In Python, we can use the modulus operator%to find the remainder of the division ofiby 5. If the remainder is 0, theniis a multiple of 5.
if i % 5 == 0:
- If
iis a multiple of 5, we printifollowed by the string 'VIT'. In Python, we can use theprint()function to print to the console. We can use thestr()function to convertito a string, and then use the+operator to concatenate this string with ' VIT'.
print(str(i) + ' VIT')
- If
iis not a multiple of 5, we just print 'VIT'.
else:
print('VIT')
Here is the complete code:
N = int(input())
for i in range(1, N+1):
if i % 5 == 0:
print(str(i) + ' VIT')
else:
print('VIT')
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