The quadratic formula is given by:

x = [-b ± sqrt(b² - 4ac)] / 2a

For the quadratic function f(x) = 2x² + 2x - 5, the coefficients are:

a = 2
b = 2
c = -5

Substituting these values into the quadratic formula gives:

x = [-2 ± sqrt((2)² - 4*2*(-5))] / 2*2
x = [-2 ± sqrt(4 + 40)] / 4
x = [-2 ± sqrt(44)] / 4
x = [-2 ± 2*sqrt(11)] / 4
x = -1/2 ± 1/2*sqrt(11)

So, the zeros of the function f(x) = 2x² + 2x - 5 are x = -1/2 + sqrt(11)/2 and x = -1/2 - sqrt(11)/2.

Question

The quadratic formula is given by:

x = [-b ± sqrt(b² - 4ac)] / 2a

For the quadratic function f(x) = 2x² + 2x - 5, the coefficients are:

a = 2
b = 2
c = -5

Substituting these values into the quadratic formula gives:

x = [-2 ± sqrt((2)² - 4*2*(-5))] / 2*2
x = [-2 ± sqrt(4 + 40)] / 4
x = [-2 ± sqrt(44)] / 4
x = [-2 ± 2*sqrt(11)] / 4
x = -1/2 ± 1/2*sqrt(11)

So, the zeros of the function f(x) = 2x² + 2x - 5 are x = -1/2 + sqrt(11)/2 and x = -1/2 - sqrt(11)/2.

Knowee AI · Accepted Answer

The quadratic formula is given by:

x = [-b ± sqrt(b² - 4ac)] / 2a

For the quadratic function f(x) = 2x² + 2x - 5, the coefficients are:

a = 2
b = 2
c = -5

Substituting these values into the quadratic formula gives:

x = [-2 ± sqrt((2)² - 4*2*(-5))] / 2*2
x = [-2 ± sqrt(4 + 40)] / 4
x = [-2 ± sqrt(44)] / 4
x = [-2 ± 2*sqrt(11)] / 4
x = -1/2 ± 1/2*sqrt(11)

So, the zeros of the function f(x) = 2x² + 2x - 5 are x = -1/2 + sqrt(11)/2 and x = -1/2 - sqrt(11)/2.

Find the zeros of the following quadratic using the quadratic formula and write down all your work in your written journal.𝑓(𝑥)=2𝑥2+2𝑥−5