The given equation is x² = 5. To put it into the standard form of a quadratic equation, which is ax² + bx + c = 0, we need to move all terms to one side of the equation.

In this case, we subtract 5 from both sides to get:

x² - 5 = 0

So, in the standard form ax² + bx + c = 0, we have:

a = 1 (the coefficient of x²)
b = 0 (since there is no x term in the equation)
c = -5 (the constant term)

Question

The given equation is x² = 5. To put it into the standard form of a quadratic equation, which is ax² + bx + c = 0, we need to move all terms to one side of the equation.

In this case, we subtract 5 from both sides to get:

x² - 5 = 0

So, in the standard form ax² + bx + c = 0, we have:

a = 1 (the coefficient of x²)
b = 0 (since there is no x term in the equation)
c = -5 (the constant term)

Knowee AI · Accepted Answer

The given equation is x² = 5. To put it into the standard form of a quadratic equation, which is ax² + bx + c = 0, we need to move all terms to one side of the equation.

In this case, we subtract 5 from both sides to get:

x² - 5 = 0

So, in the standard form ax² + bx + c = 0, we have:

a = 1 (the coefficient of x²)
b = 0 (since there is no x term in the equation)
c = -5 (the constant term)

Put the quadratic equation given into standard form to identify 𝑎, 𝑏, and 𝑐. Move terms to the left side of the equation.𝑥2=5𝑎𝑥2+𝑏𝑥+𝑐=0

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