The divisibility rule of 4 is that if the number formed by the last two digits of a number is divisible by 4, then the number is divisible by 4.

The two-digit numbers that can be formed using 5, 6, 7, 8, 9 and are divisible by 4 are: 56, 64, 68, 76, 84, 92.

So, the last two places can be filled in 6 ways.

The remaining three places can be filled in 3! = 3*2*1 = 6 ways.

Therefore, the total number of five digit numbers that can be formed is 6*6 = 36.

So, the correct option is 36.

Question

The divisibility rule of 4 is that if the number formed by the last two digits of a number is divisible by 4, then the number is divisible by 4.

The two-digit numbers that can be formed using 5, 6, 7, 8, 9 and are divisible by 4 are: 56, 64, 68, 76, 84, 92.

So, the last two places can be filled in 6 ways.

The remaining three places can be filled in 3! = 3*2*1 = 6 ways.

Therefore, the total number of five digit numbers that can be formed is 6*6 = 36.

So, the correct option is 36.

Knowee AI · Accepted Answer

The divisibility rule of 4 is that if the number formed by the last two digits of a number is divisible by 4, then the number is divisible by 4.

The two-digit numbers that can be formed using 5, 6, 7, 8, 9 and are divisible by 4 are: 56, 64, 68, 76, 84, 92.

So, the last two places can be filled in 6 ways.

The remaining three places can be filled in 3! = 3*2*1 = 6 ways.

Therefore, the total number of five digit numbers that can be formed is 6*6 = 36.

So, the correct option is 36.

How many five digit numbers can be formed using every digit of 5, 6, 7, 8 and 9 which are divisible by 4?Options36181224