How many four digit numbers can be formed using 0, 5, 2, 3, 6 such that the number is divisible by 5 (Repetition is not allowed)

To find the number of four-digit numbers that can be formed using the digits 0, 5, 2, 3, and 6, such that the number is divisible by 5 and repetition is not allowed, we can follow these steps:

Step 1: Determine the total number of choices for the thousands place. Since repetition is not allowed, we have 5 choices for the thousands place (0, 5, 2, 3, or 6).

Step 2: Determine the total number of choices for the hundreds place. Again, since repetition is not allowed, we have 4 choices for the hundreds place (excluding the digit already chosen for the thousands place).

Step 3: Determine the total number of choices for the tens place. Similarly, we have 3 choices for the tens place (excluding the digits already chosen for the thousands and hundreds places).

Step 4: Determine the total number of choices for the units place. Once again, we have 2 choices for the units place (excluding the digits already chosen for the thousands, hundreds, and tens places).

Step 5: Calculate the total number of four-digit numbers. To find the total number of four-digit numbers, we multiply the number of choices for each place value together: Total number of four-digit numbers = (Number of choices for thousands place) x (Number of choices for hundreds place) x (Number of choices for tens place) x (Number of choices for units place)

Therefore, the total number of four-digit numbers that can be formed using the digits 0, 5, 2, 3, and 6, such that the number is divisible by 5 and repetition is not allowed, is:

5 x 4 x 3 x 2 = 120

So, there are 120 four-digit numbers that meet the given conditions.