Solve the following independent system of equations.5𝑥−6𝑦=−3910𝑥−3𝑦=3𝑥= 𝑦=

To solve the system of equations:

5x - 6y = -39 10x - 3y = 3

Step 1: Multiply the second equation by 2 to make the coefficients of x in both equations the same. This gives us:

5x - 6y = -39 20x - 6y = 6

Step 2: Subtract the first equation from the new second equation. This will eliminate y:

20x - 5x = 6 - (-39) 15x = 45 x = 45 / 15 x = 3

Step 3: Substitute x = 3 into the first equation:

5(3) - 6y = -39 15 - 6y = -39 -6y = -39 - 15 -6y = -54 y = -54 / -6 y = 9

So, the solution to the system of equations is x = 3, y = 9.

Sure, let's solve the system of equations step by step.

The system of equations is:

1. 5x - 6y = -39
2. 10x - 3y = 3

Step 1: Multiply the second equation by 2 to make the coefficients of x in both equations the same. This gives us:

20x - 6y = 6

Step 2: Now we have a new system of equations:

5x - 6y = -39 20x - 6y = 6

Step 3: Subtract the first equation from the second to eliminate y. This gives us:

15x = 45

Step 4: Divide both sides by 15 to solve for x:

x = 3

Step 5: Substitute x = 3 into the first equation to solve for y:

5(3) - 6y = -39 15 - 6y = -39 -6y = -54 y = 9

So, the solution to the system of equations is x = 3, y = 9.