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Quadrilateral PQRS is a trapezoid with segment SR is parallel to segment PQ and segment SP is perpendicular to segment PQ. If PQ=25, SR=13, and RQ=13, then find the area of quadrilateral PQRS.

Question

Quadrilateral PQRS is a trapezoid with segment SR is parallel to segment PQ and segment SP is perpendicular to segment PQ. If PQ=25, SR=13, and RQ=13, then find the area of quadrilateral PQRS.

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Solution

To find the area of a trapezoid, we use the formula: Area = 1/2 * (sum of the lengths of the parallel sides) * (distance between them).

Here, the parallel sides are PQ and SR, and the distance between them is the height of the trapezoid.

We know that PQ = 25 and SR = 13.

We need to find the height of the trapezoid. We know that SP is perpendicular to PQ, so it is the height. We can find SP using the Pythagorean theorem because we know that triangle SPQ is a right triangle (since SP is perpendicular to PQ).

The Pythagorean theorem is a^2 + b^2 = c^2, where c is the hypotenuse and a and b are the other two sides.

Here, RQ is the hypotenuse and PQ and SP are the other two sides. So, we have:

SP^2 + PQ^2 = RQ^2 SP^2 + 25^2 = 13^2 SP^2 = 13^2 - 25^2 SP^2 = 169 - 625 SP^2 = -456

Since the square of a real number cannot be negative, there seems to be a mistake in the problem. The length of RQ cannot be less than the length of PQ in a right triangle. Please check the values again.

This problem has been solved

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