ABCD is a parallelogram. P, Q, R and S are the points on sides AB, BC, CD and DA respectively such that AP = DR. If the area of the parallelogram ABCD is 16 cm2, find the area of the quadrilateral PQRS.
Question
ABCD is a parallelogram. P, Q, R and S are the points on sides AB, BC, CD and DA respectively such that AP = DR. If the area of the parallelogram ABCD is 16 cm2, find the area of the quadrilateral PQRS.
Solution
The area of a parallelogram is given by the product of its base and height. In parallelogram ABCD, let's say AB is the base and h is the height. So, the area of ABCD = AB * h = 16 cm².
Since AP = DR, the line PQRS divides the parallelogram ABCD into two equal areas. This is because the height from P to SR is the same as the height from A to BC (since they are parallel), and the base AP is equal to the base DR.
Therefore, the area of quadrilateral PQRS is half the area of the parallelogram ABCD, which is 16/2 = 8 cm².
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