What type conversion is performed in the following code snippet?#include <stdio.h>int main() {int x = 5;double y = x;printf("%f", y);return 0;}Explicit type conversion.Implicit type conversion.No type conversion.Downcasting.Compilation error.
Question
What type conversion is performed in the following code snippet?#include <stdio.h>int main() {int x = 5;double y = x;printf("%f", y);return 0;}Explicit type conversion.Implicit type conversion.No type conversion.Downcasting.Compilation error.
Solution
The type conversion performed in the given code snippet is Implicit type conversion. In the code, the integer 'x' is being assigned to the double 'y'. Since double has a larger range than int, this conversion is done automatically by the compiler. This is known as Implicit type conversion or coercion.
Similar Questions
What type conversion is performed in the following code snippet?#include <stdio.h>int main() {int x = 5;double y = x;printf("%f", y);return 0;}Explicit type conversion.Implicit type conversion.No type conversion.Downcasting.Compilation error.
What is the output for the following code?
Which of the following is an example of explicit type conversion?
What does the following code snippet do?
What will be the output of the following code snippet?
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