Dominic's snow cone stand went through 6 5/6 bags of ice in the first hour it was open and 6 11/12 bags of ice the second hour. How much ice did it use during those two hours?Write your answer as a fraction or as a whole or mixed number.
Question
Dominic's snow cone stand went through 6 5/6 bags of ice in the first hour it was open and 6 11/12 bags of ice the second hour. How much ice did it use during those two hours?Write your answer as a fraction or as a whole or mixed number.
Solution
To solve this problem, we first need to add the amounts of ice used in the first and second hour.
First hour: Dominic used 6 5/6 bags of ice. This can also be written as 6 + 5/6.
Second hour: Dominic used 6 11/12 bags of ice. This can also be written as 6 + 11/12.
To add these together, we first add the whole numbers:
6 (from the first hour) + 6 (from the second hour) = 12
Next, we add the fractions:
5/6 (from the first hour) + 11/12 (from the second hour).
To add these fractions, we need to have the same denominator. The least common denominator between 6 and 12 is 12. So we convert 5/6 to 10/12.
Now we can add the fractions:
10/12 + 11/12 = 21/12
But 21/12 can be simplified to 1 9/12 or 1 3/4 (by dividing both the numerator and the denominator by 3).
So, adding this to our whole number sum:
12 (from the whole numbers) + 1 3/4 (from the fractions) = 13 3/4
Therefore, Dominic used 13 3/4 bags of ice during the first two hours.
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