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Christine made some chilli with 6 5/6 tins of black beans and 7/12 of a tin of pinto beans. How many tins of beans did Christine use in all?Write your answer as a fraction or as a whole or mixed number.

Question

Christine made some chilli with 6 5/6 tins of black beans and 7/12 of a tin of pinto beans. How many tins of beans did Christine use in all?Write your answer as a fraction or as a whole or mixed number.

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Solution

First, let's convert the mixed number 6 5/6 to an improper fraction.

To do this, we multiply the whole number (6) by the denominator of the fraction (6) and then add the numerator of the fraction (5). This gives us 36 + 5 = 41. So, 6 5/6 is the same as 41/6.

Now, we can add this to the 7/12 of a tin of pinto beans.

However, before we can add these two fractions, we need to find a common denominator. The least common multiple of 6 and 12 is 12.

So, we convert 41/6 to a fraction with 12 as the denominator. To do this, we multiply both the numerator and the denominator by 2, which gives us 82/12.

Now, we can add 82/12 and 7/12. This gives us 89/12.

89/12 is an improper fraction and can be converted to a mixed number. To do this, we divide 89 by 12. This gives us a quotient of 7 and a remainder of 5.

So, 89/12 is the same as 7 5/12.

Therefore, Christine used 7 5/12 tins of beans in all.

This problem has been solved

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