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What will be the output of the following C code?#include <stdio.h> void main() { int x = 10; int y = x++ + 20;  printf("%d,%d",x,y); return 0; }

Question

What will be the output of the following C code?#include <stdio.h> void main() { int x = 10; int y = x++ + 20;  printf("%d,%d",x,y); return 0; }

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Solution

The output of the given C code will be "11,30".

Here's the step by step explanation:

  1. The variable x is initialized with the value 10.

  2. The expression x++ + 20 is evaluated. Here, x++ is a post-increment operation which means the value of x is used first and then it is incremented. So, x++ gives 10 and then x becomes 11. Adding 20 to 10 gives 30. This result 30 is stored in the variable y.

  3. The printf function prints the values of x and y which are 11 and 30 respectively.

So, the output is "11,30".

This problem has been solved

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