To solve this problem, you can follow these steps:

1. Initialize an empty list `result` to store the results.
2. Iterate over the `nums` list using a for loop. For each number `nums[i]`:
- Initialize a variable `sum` to 0.
- Iterate over the `nums` list again using a nested for loop. For each number `nums[j]`:
- If `i` is not equal to `j`, add the absolute difference between `nums[i]` and `nums[j]` to `sum`.
- Append `sum` to `result`.
3. Return `result`.

Here is a Python solution following these steps:

```python
def sum_of_absolute_differences(nums):
result = []
for i in range(len(nums)):
sum = 0
for j in range(len(nums)):
if i != j:
sum += abs(nums[i] - nums[j])
result.append(sum)
return result
```

You can call this function with the given examples like this:

```python
print(sum_of_absolute_differences([2,3,5])) # Output: [4,3,5]
print(sum_of_absolute_differences([1,4,6,8,10])) # Output: [24,15,13,15,21]
```

This solution has a time complexity of O(n^2) because of the two nested loops. If the input list is very large, this solution might be too slow. In that case, you would need to find a more efficient algorithm.

Question

To solve this problem, you can follow these steps:

1. Initialize an empty list `result` to store the results.
2. Iterate over the `nums` list using a for loop. For each number `nums[i]`:
   - Initialize a variable `sum` to 0.
   - Iterate over the `nums` list again using a nested for loop. For each number `nums[j]`:
     - If `i` is not equal to `j`, add the absolute difference between `nums[i]` and `nums[j]` to `sum`.
   - Append `sum` to `result`.
3. Return `result`.

Here is a Python solution following these steps:

```python
def sum_of_absolute_differences(nums):
    result = []
    for i in range(len(nums)):
        sum = 0
        for j in range(len(nums)):
            if i != j:
                sum += abs(nums[i] - nums[j])
        result.append(sum)
    return result
```

You can call this function with the given examples like this:

```python
print(sum_of_absolute_differences([2,3,5]))  # Output: [4,3,5]
print(sum_of_absolute_differences([1,4,6,8,10]))  # Output: [24,15,13,15,21]
```

This solution has a time complexity of O(n^2) because of the two nested loops. If the input list is very large, this solution might be too slow. In that case, you would need to find a more efficient algorithm.

Knowee AI · Accepted Answer

To solve this problem, you can follow these steps:

1. Initialize an empty list `result` to store the results.
2. Iterate over the `nums` list using a for loop. For each number `nums[i]`:
   - Initialize a variable `sum` to 0.
   - Iterate over the `nums` list again using a nested for loop. For each number `nums[j]`:
     - If `i` is not equal to `j`, add the absolute difference between `nums[i]` and `nums[j]` to `sum`.
   - Append `sum` to `result`.
3. Return `result`.

Here is a Python solution following these steps:

```python
def sum_of_absolute_differences(nums):
    result = []
    for i in range(len(nums)):
        sum = 0
        for j in range(len(nums)):
            if i != j:
                sum += abs(nums[i] - nums[j])
        result.append(sum)
    return result
```

You can call this function with the given examples like this:

```python
print(sum_of_absolute_differences([2,3,5]))  # Output: [4,3,5]
print(sum_of_absolute_differences([1,4,6,8,10]))  # Output: [24,15,13,15,21]
```

This solution has a time complexity of O(n^2) because of the two nested loops. If the input list is very large, this solution might be too slow. In that case, you would need to find a more efficient algorithm.

Question

Solution

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