bpskmod = comm.BPSKModulatorhint: execute the instruction before answering 1.creates a modulator System object™ that modulates the input signal using the binary frequency shift keying (BFSK) method.2.the phase offset when the above command is used is 03. the output data after executing this instruction would be 1+i0 or -1+i0Select one:a. 1 correct, 2, 3 incorrectb. 1,3 correct, 2 incorrectc. 1,2 correct 3, incorrectd. all correcte. all incorrect
Question
bpskmod = comm.BPSKModulatorhint: execute the instruction before answering 1.creates a modulator System object™ that modulates the input signal using the binary frequency shift keying (BFSK) method.2.the phase offset when the above command is used is 03. the output data after executing this instruction would be 1+i0 or -1+i0Select one:a. 1 correct, 2, 3 incorrectb. 1,3 correct, 2 incorrectc. 1,2 correct 3, incorrectd. all correcte. all incorrect
Solution
The correct answer is b. 1,3 correct, 2 incorrect.
The command "comm.BPSKModulator" indeed creates a modulator System object that modulates the input signal using the binary phase shift keying (BPSK) method, not binary frequency shift keying (BFSK). Therefore, statement 1 is correct.
The phase offset when the above command is used is not necessarily 0. It depends on the specific parameters set when the BPSKModulator object is created. Therefore, statement 2 is incorrect.
The output data after executing this instruction would indeed be 1+i0 or -1+i0. In BPSK, the binary input data is represented as two different phases of the carrier signal, typically 0 and π. These phases correspond to the complex numbers 1+i0 and -1+i0. Therefore, statement 3 is correct.
Similar Questions
BPSK is a phase modulation in which 4 symbols 00,01,11,10 are modulated by phases 0,90,18,270Select one:TrueFalse
choose the program for BPSK which is executable and will display error rate and demodulated data Select one:a.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k);txSig = pskmod(dataIn,M);rxSig = awgn(txSig,snr);rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)b.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k)txSig = pskmod(dataIn,M)rxSym = pskdemod(rxSig,M);nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)c.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k)txSig = pskmod(dataIn,M)rxSig = awgn(txSig,snr)rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)d.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k);txSig = pskmod(dataIn,M)rxSig = awgn(txSig,snr)rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)
Explain the generation and detection of BPSK scheme.
if data sequence is 0 1 0 0 0 1 01 0the phase of BPSK waveform will vary as Select one:a. pi 0 pi pi pi 0 pi 0 pib. 0 0 pi pi 0 0 pi 0 pic. 0 0 pi pi pi 0 pi 0 pi
Consider a binary data sequence of bit rate 8992 Hz modulated by a carrier of 21031 Hz to obtain BPSK.*i) Calculate the bandwidthanswer format example if answer is 3.5khz write as 3500 ( only number) don't write as 3.5khz
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