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Consider a binary data sequence of bit rate 8992 Hz modulated by a carrier of 21031 Hz to obtain BPSK.*i) Calculate the bandwidthanswer format example if answer is 3.5khz   write as 3500 ( only number) don't write as 3.5khz

Question

Consider a binary data sequence of bit rate 8992 Hz modulated by a carrier of 21031 Hz to obtain BPSK.*i) Calculate the bandwidthanswer format example if answer is 3.5khz   write as 3500 ( only number) don't write as 3.5khz

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Solution

In BPSK (Binary Phase Shift Keying), the bit rate is equal to the baud rate. This means that for each bit, there is one signal element. Therefore, the bandwidth for BPSK can be calculated using the formula:

Bandwidth (B) = 2 * Bit rate

Given that the bit rate is 8992 Hz, we can substitute this into the formula:

B = 2 * 8992 Hz

B = 17984 Hz

So, the bandwidth is 17984.

Similar Questions

Consider a BPSK modulated signal with bandwidth  15900 Hz i) Calculate the input  data rateanswer format example if answer is 3.5khz   write as 3500 ( only number) don't write as 3.5khz

Consider a BPSK modulated signal with bandwidth  19371 Hz i) Calculate the input  data rate

choose the program for BPSK which is executable and will display error rate and demodulated data  Select one:a.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k)txSig = pskmod(dataIn,M)rxSig = awgn(txSig,snr)rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)b.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k);txSig = pskmod(dataIn,M);rxSig = awgn(txSig,snr);rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)c.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k);txSig = pskmod(dataIn,M)rxSig = awgn(txSig,snr)rxSym = pskdemod(rxSig,M);round(rxSym)nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)d.M = 2; % Modulation orderk = log2(M); % Bits per symbolsnr=10;numSymPerFrame = 50;dataIn = randi([0 k],numSymPerFrame,k)txSig = pskmod(dataIn,M)rxSym = pskdemod(rxSig,M);nErrors = biterr(dataIn, rxSym);[nErrors err_rate] = biterr(dataIn, rxSym)

For FSK, the bit rate is equal to the baud rate (symbols/seconds).Group of answer choicesTrueFalse

Explain the generation and detection of BPSK scheme.

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