A sphere of radius, r = 2 cm, creates an electric field of strength, E = 3 N/C, at a distance, d = 5 cm from the centre of the sphere. Determine the electric charge on the sphere.

A solid sphere with radius a = 2 cm has a total charge Q = 10 nC which is uniformly distributed throughout its volume. Using Gauss’s Law, determine the magnitude of the electric field at a point 1 cm from the center of the sphere.Multiple Choice1.12 × 105 N/C1.12 × 105 N/C2.25 × 105 N/C2.25 × 105 N/C0 N/C3.61 × 105 N/C

A spherical charge distribution given byρ = ρ0 (1 −r2a2) if r ≤ aρ = 0 if r > aIf a is radius of sphere. Find the electric field at a distance r from the center when r>a and r<a. Alsoshow that electric field will be maximum when r =√5 a3

A solid conducting sphere of radius R is charged such that the magnitude of the electric field at the surface of the sphere is 4.239 ⋅ 105 V/m4.239 · 105 V/m . The potential 28.37 cm from the surface of the sphere is 6.288E5 V. What is the radius R of the sphere?

A -2.34-nC point charge is located at the center of a conducting spherical shell. The shell has an inner radius of 2.00 m, an outer radius of 4.00 m, and a charge of 8.53-nC. (a) What is the magnitude of the electric field at r = 1.00 m?  N/C (b) What is the magnitude of the electric field at r = 3.00 m?  N/C (c) What is the magnitude of the electric field at r = 5.00 m?  N/C (d) What is the surface charge density, σ, on the outside surface of the shell? (You may enter your calculation using scientific notation.)  C/m2C/m2

Charge Q is distributed uniformly throughout the vol- ume of an insulating sphere of radius R = 4.00 cm. At a distance of 1 r= 8.00 cm from the center of the sphere, the electric field due to the charge distribution has magnitude E 940 N/C. What are (a) the vol- ume charge density for the sphere and (b) the electric field at a distance of 2.00 cm from the sphere's center?