Charge Q is distributed uniformly throughout the vol- ume of an insulating sphere of radius R = 4.00 cm. At a distance of 1 r= 8.00 cm from the center of the sphere, the electric field due to the charge distribution has magnitude E 940 N/C. What are (a) the vol- ume charge density for the sphere and (b) the electric field at a distance of 2.00 cm from the sphere's center?

A solid sphere with radius a = 2 cm has a total charge Q = 10 nC which is uniformly distributed throughout its volume. Using Gauss’s Law, determine the magnitude of the electric field at a point 1 cm from the center of the sphere.Multiple Choice1.12 × 105 N/C1.12 × 105 N/C2.25 × 105 N/C2.25 × 105 N/C0 N/C3.61 × 105 N/C

A sphere of radius, r = 2 cm, creates an electric field of strength, E = 3 N/C, at a distance, d = 5 cm from the centre of the sphere. Determine the electric charge on the sphere.

A -2.34-nC point charge is located at the center of a conducting spherical shell. The shell has an inner radius of 2.00 m, an outer radius of 4.00 m, and a charge of 8.53-nC. (a) What is the magnitude of the electric field at r = 1.00 m?  N/C (b) What is the magnitude of the electric field at r = 3.00 m?  N/C (c) What is the magnitude of the electric field at r = 5.00 m?  N/C (d) What is the surface charge density, σ, on the outside surface of the shell? (You may enter your calculation using scientific notation.)  C/m2C/m2

A solid sphere of radius R has electric charge density given by  𝜌 = a/r , where a is constant. Find the electric field within the charge distribution as a function of r. Note: The volume element dV for a spherical shell of radius r and thickness dr is equal to 4𝜋r2dr. (Use the following as necessary: a, r, and 𝜀0. Consider that a is positive.)

A solid sphere of radius R𝑅 has a charge Q𝑄 distributed in its volume with a charge density ρ𝜌 =kra=𝑘𝑟𝑎, where k𝑘 and a𝑎 are constants and r𝑟 is the distance from its centre. If the electric field at r=𝑟= R2𝑅2 is 1818 times that at r=R,𝑟=𝑅, the value of a𝑎 is