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Differentiate the function y = tan(5x-4)

Question

Differentiate the function y = tan(5x-4)

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Solution

To differentiate the function y = tan(5x-4), we will use the chain rule. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function.

Step 1: Identify the outer and inner functions. Here, the outer function is tan(u) and the inner function is 5x-4.

Step 2: Differentiate the outer function. The derivative of tan(u) with respect to u is sec^2(u).

Step 3: Differentiate the inner function. The derivative of 5x-4 with respect to x is 5.

Step 4: Apply the chain rule. According to the chain rule, the derivative of y with respect to x is the derivative of the outer function times the derivative of the inner function.

So, dy/dx = (sec^2(u)) * 5 = 5sec^2(5x-4).

Therefore, the derivative of the function y = tan(5x-4) is dy/dx = 5sec^2(5x-4).

This problem has been solved

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To find the derivative of \( 5 \tan(\ln x) \), we will use the chain rule. Let \( u = \ln x \). Then, the function becomes \( 5 \tan(u) \). First, find the derivative of \( 5 \tan(u) \) with respect to \( u \): \[ \frac{d}{du} [5 \tan(u)] = 5 \sec^2(u) \] Next, find the derivative of \( u = \ln x \) with respect to \( x \): \[ \frac{du}{dx} = \frac{1}{x} \] Now, apply the chain rule: \[ \frac{d}{dx} [5 \tan(\ln x)] = 5 \sec^2(\ln x) \cdot \frac{1}{x} \] So, the derivative is: \[ \frac{5 \sec^2(\ln x)}{x} \] Therefore, the correct answer is: \[ \boxed{C} \]

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