Consider the following method that is intended to swap the values of two integers:1234567891011public static void falseSwap(int a, int b) {    int temp = a;    a = b;    b = temp;}public static void main(String[] args) {    int x = 3;    int y = 4;    falseSwap(x, y);    System.out.println(x + " " + y);}Why doesn’t the falseSwap method swap the contents of x and y?

How do you swap two numbers without using a third variable in Java?

write a program in java to display the number after swapping without using third variable

Swapping of two numbers is an intermediate step in any sorting algorithm, In the lecture we use a temporary variable to swap two elements in the list.Can swapping of two numbers be done without using a temporary variable? Yes No Depends on size of list Depends on nature of elements in the list

Consider the following C functionvoid swap (int a, int b){    int temp;    temp = a;     a = b;     b = temp;}.In order to exchange the values of two variables x and y.a.Call swap (x, y)b.Call swap (&x, &y)c.swap(x,y) cannot be used as it does not return any valued.swap(x,y) cannot be used as the parameters are passed by value

What is the purpose of the swap function in this program?*1 pointA. To swap the positions of two adjacent elements in the array.B. To swap the values of two variables in the main function.C. To swap the elements at the beginning and end of the array.D. To swap the positions of every two elements in the array.After the fourth pass, what is the array state?*1 pointA. {1, 2, 4, 3, 5, 6, 7, 8, 9, 10}B. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}C. {2, 1, 4, 5, 7, 3, 8, 6, 9, 10}D. {10, 9, 8, 7, 6, 5, 4, 3, 2, 1}