Swapping of two numbers is an intermediate step in any sorting algorithm, In the lecture we use a temporary variable to swap two elements in the list.Can swapping of two numbers be done without using a temporary variable? Yes No Depends on size of list Depends on nature of elements in the list
Question
Swapping of two numbers is an intermediate step in any sorting algorithm, In the lecture we use a temporary variable to swap two elements in the list.Can swapping of two numbers be done without using a temporary variable? Yes No Depends on size of list Depends on nature of elements in the list
Solution
Yes, swapping of two numbers can be done without using a temporary variable. This can be achieved using arithmetic operations or bitwise XOR operation. Here is how you can do it:
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Arithmetic Operations:
- Let's say we have two numbers a and b. We want to swap these numbers.
- First, we add these numbers and store the result in a. So, a = a + b.
- Then, we subtract b (which is the original a) from the new a (which is a + b). This gives us the original b. So, b = a - b.
- Finally, we subtract the new b (which is the original a) from a (which is a + b). This gives us the original a. So, a = a - b.
- Now, a and b have been swapped without using a temporary variable.
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Bitwise XOR Operation:
- Again, let's say we have two numbers a and b.
- First, we perform the XOR operation on a and b and store the result in a. So, a = a ^ b.
- Then, we perform the XOR operation on the new a (which is a ^ b) and b (which is the original a). This gives us the original b. So, b = a ^ b.
- Finally, we perform the XOR operation on a (which is a ^ b) and the new b (which is the original a). This gives us the original a. So, a = a ^ b.
- Now, a and b have been swapped without using a temporary variable.
Please note that these methods should be used with caution as they can lead to overflow in some cases.
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