What is the solution to the equation below? 2 x x − 2 − x + 3 x − 4 = − 4 x x 2 − 6 x + 8 2 𝑥 𝑥 − 2 − 𝑥 + 3 𝑥 − 4 = − 4 𝑥 𝑥 2 − 6 𝑥 + 8 option 1 of 4 x = 2 , 3 𝑥 = 2 , 3 x = 2 , 3 𝑥 = 2 , 3 option 1 of 4 option 2 of 4 x = 2 𝑥 = 2 x = 2 𝑥 = 2 option 2 of 4 option 3 of 4 x = 3 𝑥 = 3 x = 3 𝑥 = 3 option 3 of 4 option 4 of 4 x = 2 , 4 𝑥 = 2 , 4 x = 2 , 4 𝑥 = 2 , 4 option 4 of 4

What is the solution of the equation? 2 x = 1 32 2 𝑥 = 1 32 option 1 of 4 − 16 − 16 − 16 − 16 option 1 of 4 option 2 of 4 1 16 1 16 1 16 1 16 option 2 of 4 option 3 of 4 1 5 1 5 1 5 1 5 option 3 of 4 option 4 of 4 − 5 − 5 − 5 − 5 option 4 of 4

x 2 −4x−16=−4x

Find the missing number so that the equation has infinitely many solutions.–4x+=–2(2x+1)

3(6x−64​+4)=4x−2